Formation of polyethylene from calcium carbide takes place as follows

$C a C_{2} + 2 H_{2} O \to C a (O H)_{2} + C_{2} H_{2}$

$C_{2} H_{2} + H_{2} \to C_{2} H_{4}$

$n (C_{2} H_{4}) \to (- C H_{2} - C H_{2} -)_{n}$

The mass of polyethylene obtained in kg from 64 kg $C a C_{2}$ is

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TestHub · Accepted Answer

C a C 2 64 g + 2 H 2 O → C a ( O H ) 2 + C 2 H 2 C 2 H 2 + H 2 → C 2 H 4 28 g 64g of C a C 2 gives 28g of ethylene ∴ 64kg of C a C 2 will give 28kg of polyethylene

Chemistry - Polymers Question with Solution | TestHub

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