Chemistry - Polymers Question with Solution | TestHub

Moles of$\mathrm{C}\mathrm{a}{\mathrm{C}}_2=\frac{64\times 10^3}{64}\cong 1\times 10^3$

So from the balanced chemical equation, moles of${\mathrm{C}}_2{\mathrm{H}}_2=$moles of${\mathrm{C}}_2{\mathrm{H}}_4$

$=$moles of$\mathrm{C}\mathrm{a}{\mathrm{C}}_2=1\times 10^3$

So moles of polythene$=\frac{1}{\mathrm{n}}\times 1\times 10^3$

So weight of polythene$=\frac{1}{\mathrm{n}}\times 1\times 1\times 28\mathrm{n}$kg

= 28 kg