Match Lis-I with List-II. List-1 List-II A. Weak intermolecular forces of attraction I. Hexamethylenediamine + adipic acid B. Hydrogen bonding II. AlEt 3 + TiCl 4 C. Heavily branched polymer III. 2 -

Question

Match Lis-I with List-II.

	List-1		List-II
A.	Weak intermolecular forces of attraction	I.	Hexamethylenediamine + adipic acid
B.	Hydrogen bonding	II.	${AlEt}_{3} + {TiCl}_{4}$
C.	Heavily branched polymer	III.	$2 - chloro - 1, 3 - butadiene$
D.	High density polymer	IV.	$Phenol + formaldehyde$

Choose the correct answer from the options given below

TestHub · Accepted Answer

(A) Weak Intermolecular Forces are present in polymer of $2 -$ chloro, $1, 3 -$ butadiene.It is a monomer of neoprene which is a rubber(elastomer.).
(B). Hydrogen Bonding is present in NYLON $- 6, 6$ which is a polymer of Hexamethylenediamine and adipic acid. This hydrogen bonding is due to the presence of amide group.
(C) Heavily branched polymer is Bakelite which is polymer of phenol and formaldehyde. It is a crosslinked polymer.
(D) High density polymer(polyethylene) preparation requires $Al (Et)_{3}$ and ${TiCl}_{4}$ as a catalyst (Ziegler Natta Catalyst)

Chemistry - Polymer Question with Solution | TestHub

Options:

Doubts & Discussion