Arrange the following in increasing order of their intermolecular forces:
Nylon -6,6 (I), Buna –S (II), Polythene (III)

Question

Arrange the following in increasing order of their intermolecular forces: Nylon -6,6 (I), Buna –S (II), Polythene (III)

TestHub · Accepted Answer

Nylon- 6, 6 are fibres and these are polymers which have strong intermolecular forces such as hydrogen bonding. Buna- S is an elastomer and has weak intermolecular forces. Polyethylene are thermoplastics in which intermolecular forces of attraction are neither very strong nor very weak. Based on it the correct order is I > III > II.

Chemistry - Polymer Question with Solution | TestHub

Options:

Doubts & Discussion