The graph between electronegativity in Pauling scale vs $\frac{1}{r ^{2}}$ is given below for the two elecments 'X' and 'Y' respectively. (Given : $tan θ_{2} > tan θ_{1}$ )
Choose the correct option(s).

Question

The graph between electronegativity in Pauling scale vs r 2 1 ​ is given below for the two elecments 'X' and 'Y' respectively. (Given : tan θ 2 ​ > tan θ 1 ​ ) Choose the correct option(s).

TestHub · Accepted Answer

The graph follows the Allred-Rochow electronegativity relation: $χ_{P} = 0.359 \frac{Z _{e ff}}{r ^{2}} + 0.744$ .

Option A is correct: The Y-intercept is a constant ( $0.744$ ) for all elements, so $C_{1} = C_{2}$ .

Option B is correct: The slope equals $0.359 Z_{e ff}$ , and since $tan θ_{2} > tan θ_{1}$ , $Z_{e ff}$ of 'Y' is greater than 'X'.

Option C is correct: Electronegativity values on the Mulliken scale ( $χ_{M}$ ) are always greater than on the Pauling scale ( $χ_{M} \approx 2.8 \times χ_{P}$ ).

Option D is correct: Since 'X' and 'Y' have different slopes and electronegativity properties, they have an electronegativity difference ( $Δ χ \neq = 0$ ), making the X–Y bond polar.

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Options:(select one or more)

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