Chemistry - PERIODIC TABLE Question with Solution | TestHub

ChemistryPERIODIC TABLEIonisation Energy,Medium2 minQB
ChemistryMediumnumerical
Passage / Comprehension

For an isolated gaseous atom, the amount of energy supplied to remove the most loosely bonded electron is termed as Ionization energy. Successive Ionization energy values always keep on increasing due to increasing value of on outermost electron. However, due to stable configuration arrangements, sometimes the energy required is more than expected which may lead to abrupt increase in the values of Ionization energies.

The successive IE values of an element "X" of P-Block () are given below (in eV/atom)

10.36 , 23.33 , 34.79 , 47.22 , 72.59 , 88.05 , 280.94 , 328.75

 

The number of elements mentioned below having Higher value of IE1 compared to element X is ___

 

Ne, O, P, Cl, Ar, He, Na, Mg, Al, F

Answer:
7.00
Solution:

Element has6 valence electrons.It cannot be Oxygen since 8 values of IE are given. Hence the element is Sulphur.

Stream:JEESubject:ChemistryTopic:PERIODIC TABLESubtopic:Ionisation Energy,
2mℹ️ Source: QB

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