Chemistry - PERIODIC TABLE Question with Solution | TestHub

A → Correct : Atomic size → increases down the group and decreases along the period.

So, $\mathrm{O}<\mathrm{C}<\mathrm{S}<$ Se

B → Correct: 1st IP → Increases along the period. Also fully / half filled configuration has more I.P. than next neighbour.

So, $\mathrm{Na}<\mathrm{Al}<\mathrm{Mg}<\mathrm{Si}$

$\mathrm{C}\to$ Incorrect : Basic character → Increases down the group.

So, ${\mathrm{Cs}}_2\mathrm{O}>{\mathrm{K}}_2\mathrm{O}$

$\mathrm{D}\to$ Incorrect : Acidic character is higher for higher oxidation state.

So, ${\mathrm{P}}_4{\mathrm{O}}_{10}<{\mathrm{SO}}_3<{\mathrm{Cl}}_2{\mathrm{O}}_7\to$ correct order.

$\begin{array}{lll}+5& +6& +7\end{array}$