Chemistry - PERIODIC TABLE Question with Solution | TestHub

ChemistryPERIODIC TABLEIonisation Energy,Medium2 minQB
ChemistryMediummatching list

Match the column - I with column - II and select CORRECT code for your answer :-

 

Column - I

Column - II

(A)

(P) Decreasing order of IE

(B)

(Q) Increasing order of Radius

(C)

(R) Increasing order of EA

(D)

(S) Increasing number of valence shell electrons

 

(T) Increasing Z/e ratio

 

Options:

Answer:
A
Solution:

(A) Li, Na, K

Down the group:

Ionization energy (IE) decreases → (P) Decreasing order of IE

Atomic radius increases → (Q) Increasing order of radius

(B) Mg, Ca, Sr

Down Group 2:

IE decreases → (P)

Radius increases → (Q)

(C) Li, Be, B

Across Period 2:

Number of valence electrons increases (1 → 2 → 3) → (S)

(D) Na⁺, Mg²⁺, Al³⁺

These are isoelectronic species (all have 10 electrons)

With increasing nuclear charge:

Electron affinity trend (effective attraction) increases → (R)

Z/e ratio increases → (T)

 

Stream:JEESubject:ChemistryTopic:PERIODIC TABLESubtopic:Ionisation Energy,
⏱ 2mℹ️ Source: QB

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