Chemistry - PERIODIC TABLE Question with Solution | TestHub

The spin-only magnetic moment (${\mu }_s$) is calculated using the formula ${\mu }_s=\sqrt{n(n+2)}$ BM, where $n$ is the number of unpaired electrons.

For Zn²⁺:

1. The atomic number of Zn is 30.

2. The electronic configuration of Zn is $[Ar]3d^{10}4s^2$.

3. For Zn²⁺, two electrons are removed from the 4s orbital, making its configuration $[Ar]3d^{10}$.

4. In the $3d^{10}$ configuration, all five $d$ orbitals are fully filled, meaning there are no unpaired electrons ($n=0$).

5. Therefore, ${\mu }_s=\sqrt{0(0+2)}=\sqrt{0}=0$ BM.

The spin-only magnetic moment of the dipositive ion of Zn (Zn²⁺) is 0 BM.