If electronegativity of an element is 3.5 on Pauling scale and ionisation energy is 15 eV / atom then find electron affinity of that element in eV / atom

Question

TestHub · Accepted Answer

The Mulliken scale relates electronegativity ( $χ_{M}$ ) to ionization energy (IE) and electron affinity (EA) by the formula:

$χ_{M} = \frac{I E + E A}{2}$

The Pauling scale ( $χ_{P}$ ) and Mulliken scale are related by:

$χ_{P} = \frac{χ _{M}}{2.8} or χ_{M} = 2.8 \times χ_{P}$

Given $χ_{P} = 3.5$ and IE = 15 eV/atom.

First, calculate $χ_{M}$ :

$χ_{M} = 2.8 \times 3.5 = 9.8 e V$

Now, use the Mulliken formula to find EA:

$9.8 = \frac{15 + E A}{2}$

$19.6 = 15 + E A$

$E A = 19.6 - 15 = 4.6 e V / a t o m$

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