If ' M 2 X ' (ionic compound) is dissolved in water, where, the hydration energy of M + ion is 100 kJ / mol . and that of X 2 − ion is 200 kJ / mol and the lattice energy of M 2 X is 150

Question

If ' M 2 ​ X ' (ionic compound) is dissolved in water, where, the hydration energy of M + ion is 100 kJ / mol . and that of X 2 − ion is 200 kJ / mol and the lattice energy of M 2 ​ X is 150 kJ / mol . Then the heat of dissolution is ' ____ ′ kJ / mol − Heat of dissolution cycle for ionic compound is

TestHub · Accepted Answer

The heat of dissolution ( Δ H so l ​ ) is calculated by summing the lattice dissociation energy and the total hydration energies of the constituent ions. Formula: Δ H so l ​ = Δ H l a tt i ce ​ + [ 2 × Δ H h y d ​ ( M + ) + Δ H h y d ​ ( X 2 − )] Substitution: Δ H so l ​ = 150 + [ 2 ( − 100 ) + ( − 200 )] Calculation: Δ H so l ​ = 150 − 200 − 200 = − 250 k J / m o l The correct option is (B) -250.

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