Calculate the electronegativity of chlorine from the bond energies of ClF ( 61 K . Cal / mol ) . F 2 ( 38 k . Cal / mol and Cl 2 ( 58 k . cal / mol ) ( E . N of F = 4.0 )

Question

Calculate the electronegativity of chlorine from the bond energies of ClF ( 61 K . Cal / mol ) . F 2 ​ ( 38 k . Cal / mol and Cl 2 ​ ( 58 k . cal / mol ) ( E . N of F = 4.0 )

TestHub · Accepted Answer

Δ = D ( ClF ) − D ( F 2 ​ ) D ( Cl 2 ​ ) ​ ​ = 61 − 38 × 58 ​ = 14 k ⋅ Cal / mol ​ ​ ​ EN ( F ) − EN ( Cl ) = 0.208 Δ ​ En ( Cl ) = En ( F − 0.208 Δ ​ ) = 4.0 − 0.78 = 3.2

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