First and third ionization energy of Na are $496 kJ /$ mole and $6910 kJ /$ mole respectively. From the following given value of ionization energy select the correct second ionization energy of Na is :
(I) $9540 kJ / mole$
(II) $300 kJ / mole$
(III) $621 kJ / mole$
(IV) $4560 kJ / mole$

Question

First and third ionization energy of Na are $496 kJ /$ mole and $6910 kJ /$ mole respectively. From the following given value of ionization energy select the correct second ionization energy of Na is :

(I) $9540 kJ / mole$

(II) $300 kJ / mole$

(III) $621 kJ / mole$

(IV) $4560 kJ / mole$

TestHub · Accepted Answer

Explanation: The value of I.E. is given, and we are asked to predict another value of I.E.

Concept: $I E_{1} < I E_{2} < I E_{3} \dots$ .

Solution/Explanation/Calculation:

Na IE₁ → 496 kJ/mol

IE₂ → ?

IE₃ → 6910 kJ/mol

We know that ionization energy (IE) has successive values; thus, IE₂ lies between the values of IE₁ and IE₃.

Therefore, according to the options, its value is 4560 kJ/mol.

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