Chemistry - PERIODIC TABLE Question with Solution | TestHub
ChemistryPERIODIC TABLEIntroduction, NamingHard2 minQB
ChemistryHardinteger
Calculate , where
Number of species having greater size than among
Y = Maximum number of elements which can be present in period if each orbital can accomodated .
Answer:
93
Solution:
Only Mg2+ and Al3+ are smaller than Na+
Hence X=7
For Y;
Total number of elements in a period = xN2
x = Maximum possible values of spin quantum number
N =(n+2)/2 if "n"(period number) is even
N=(n+1)/2 if "n"(period number) is odd
For 8th period; x=4
N =5
Y =100
Stream:JEESubject:ChemistryTopic:PERIODIC TABLESubtopic:Introduction, Naming
⏱ 2mℹ️ Source: QB
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