The number of correct orders among the following? (i) N 2 O 5 CH 4 (Acidic nature) (iii) Li Na K Rb Cs (Ionis

Question

The number of correct orders among the following?

(i) $N_{2} O_{5} < P_{4} O_{10} < As_{4} O_{10}$ (Acidic nature)

(ii) $H_{3} PO_{4} > H_{2} S > CH_{4}$ (Acidic nature)

(iii) $Li > Na > K > Rb > Cs$ (Ionisation potential)

(iv) $F < Cl > Br > I > S$ (Electron affinity)

(v) $CH_{4} > NH_{3} > H_{2} O > OF_{2}$ (Bond angle)

(vi) $SO_{3} > Cl_{2} O_{7} > N_{2} O_{4}$ (Acidic nature)

(vii) $BeO < MgO < CaO < Na_{2} O$ (Basic nature)

TestHub · Accepted Answer

The 5 correct statements are (ii), (iii), (iv), (v), and (vii).

Orders (i) and (vi) are incorrect because acidic nature generally increases with electronegativity and oxidation state ( $N_{2} O_{5} > P_{4} O_{10}$ and $C l_{2} O_{7} > S O_{3}$ ).

(iii) and (iv) are correct as Ionization Potential decreases down a group, and Chlorine has a higher Electron Affinity than Fluorine due to less electronic repulsion.

(v) follows VSEPR theory where bond angles decrease as lone pairs increase ( $C H_{4} > N H_{3} > H_{2} O$ ), and (vii) correctly shows basicity increasing down the group and towards alkali metals.

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