Chemistry - PERIODIC TABLE Question with Solution | TestHub

General outer electronic configuration of ${16}^{\mathrm{th}}$ group elements is ${\mathrm{ns}}^2{\mathrm{np}}^4$

${16}^{\mathrm{th}}$ group element belonging to $4^{\mathrm{th}}$ period is $\mathrm{Se}$ and its outer electronic configuration is $4{\mathrm{s}}^{2}4{\mathrm{p}}^4$. The element present above selenium is sulphur and the outer electronic configuration of sulphur is $3{\mathrm{s}}^{2}3{\mathrm{p}}^4$.