Chemistry - PERIODIC TABLE Question with Solution | TestHub

ChemistryPERIODIC TABLEMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

If the dipole moment of AB molecule is given by 1.2 D and A-B the bond length is $1$ $Å$ then % ionic character of the bond is
[Given: $1debye = 10^{- 18} esu . cm$ ]

Options:

Answer:

Solution:

$μ_{C a l} = 4.8 \times 1 0^{- 10} e . s . u \times 1 0^{- 8} c m$

$= 4.8 \times 1 0^{- 18} e s u c m$

$= 4 . 8 D$

Hence $% ionic character = \frac{μ_{experimental}}{μ_{calculated}} \times 100$
$= \frac{1.2}{4.8} \times 100 = 25 %$

Stream:NTA_ABHYASSubject:ChemistryTopic:PERIODIC TABLESubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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