Chemistry - PERIODIC TABLE Question with Solution | TestHub

ChemistryPERIODIC TABLEMiscellaneous/MixedEasy2 minPYQ_2020
ChemistryEasynumerical

The values of electronegativity of atomAandBare 1.20 and 4.0 respectively. The percentage of ionic character ofA-Bbond is nearly

Answer:
72.24
Solution:

% ionic character of a bond is determined with the help of Hanny-Smith's equation.

% ionic characters =1.6( ΔEN )+3.5 ( ΔEN ) 2

Where, ΔEN  =difference of electronegativity=

4.01.2 = 2.80

So, % ionic character =1.6( 2.80 )+3.5 ( 2.80 ) 2 =72.24%

Stream:NTA_ABHYASSubject:ChemistryTopic:PERIODIC TABLESubtopic:Miscellaneous/Mixed
2mℹ️ Source: PYQ_2020

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