Chemistry - PERIODIC TABLE Question with Solution | TestHub

Here the order of first ionization energy is as follows
$\mathrm{N}\mathrm{e}>\mathrm{F}>\mathrm{N}>\mathrm{O}>\mathrm{C}>\mathrm{B}\mathrm{e}>\mathrm{B}>\mathrm{L}\mathrm{i}$
Hence six elements have more first ionization energy then boron.