Chemistry - PERIODIC TABLE Question with Solution | TestHub

A. Correct order$\to \mathrm{C}{\mathrm{a}}^{2+}>{\mathrm{K}}^{+}>\mathrm{C}{\mathrm{l}}^{-}>{\mathrm{S}}^{2-}$(ionization energy)
for isoelectronic species (I.E.$\propto {\mathrm{Z}}_{\mathrm{e}\mathrm{f}\mathrm{f}}$)
B. Correct order$\to \mathrm{C}<\mathrm{N}<\mathrm{F}<\mathrm{O}$(2nd I.E.)
Second electron removal from oxygen requires more energy as it acquires stable$2{\mathrm{s}}^{2}2{\mathrm{p}}^3$configuration after removal of one electron.
C.$\to \mathrm{B}>\mathrm{T}\mathrm{l}>\mathrm{I}\mathrm{n}>\mathrm{G}\mathrm{a}>\mathrm{A}\mathrm{l}$(Electronegativity)
In general EN increases in boron family from top to bottom due to increase in${\mathrm{Z}}_{\mathrm{e}\mathrm{f}\mathrm{f}}$on valence shell while boron has highest E.N. due to its vary small size.
D. Correct order$\to \mathrm{N}{\mathrm{a}}^{+}>\mathrm{L}{\mathrm{i}}^{+}>\mathrm{M}{\mathrm{g}}^{2+}>\mathrm{A}{\mathrm{l}}^{3+}>\mathrm{B}{\mathrm{e}}^{2+}$(Ionic radius)
Ionic radius depends on${\mathrm{Z}}_{\mathrm{e}\mathrm{f}\mathrm{f}}$and number of shells.