The treatment of CH 3 OH with CH 3 MgI release 1.04mL of a gas at STP. The mass of CH 3 OH added is

n g a s = 22400 1.04 = n C H 3 O H W C H 3 O H = 22400 1.04 × 32 g W C H 3 O H ≈ 1.49 m g

Chemistry - ORGANOMETALLIC COMPOUNDS Question with Solution | TestHub

ChemistryORGANOMETALLIC COMPOUNDSREACTIONS OF GRIGNARD REAGENTSMedium2 min

ChemistryMediumsingle choice

The treatment of CH₃OH with CH₃MgI release 1.04mL of a gas at STP. The mass of CH₃OH added is

Answer:

Solution:

$n_{g a s} = \frac{1.04}{22400} = n_{_{C H_{3} O H}}$

$W_{C H_{3} O H} = \frac{1.04}{22400} \times 32 g$

$W_{C H_{3} O H} \approx 1.49 m g$

Stream:JEESubject:ChemistryTopic:ORGANOMETALLIC COMPOUNDSSubtopic:REACTIONS OF GRIGNARD REAGENTS

⏱ 2m

Loading discussions...