List - I (Compound) List - II (Statement for compound) (P) (1) Odd number of double bond equivalent (Q) (2) sp 2 & sp 3 carbons are present (R) (3) It is bicyclo compound (S) CH 3 − CH = CH − C ≡ CH

Question

List - I (Compound) List - II (Statement for compound) (P) (1) Odd number of double bond equivalent (Q) (2) sp 2 & sp 3 carbons are present (R) (3) It is bicyclo compound (S) CH 3 ​ − CH = CH − C ≡ CH (4) It is spiro compound (5) All carbons are sp 2 hybridised

TestHub · Accepted Answer

(P) has six sp 2 and one sp 3 atom. (S) has DOU = 3

Chemistry - Nomenclature Question with Solution | TestHub

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Doubts & Discussion

JEE Main 2028 (Class 11)

JEE Advanced 2027 (Class 12+)

List - I (Compound)	List - II (Statement for compound)
(P)	(1) Odd number of double bond equivalent
(Q)	(2) $sp^{2} & sp^{3}$ carbons are present
(R)	(3) It is bicyclo compound
(S) $CH_{3} - CH = CH - C \equiv CH$	(4) It is spiro compound
	(5) All carbons are $sp^{2}$ hybridised