Chemistry - Nomenclature Question with Solution | TestHub

ChemistryNomenclatureMiscellaneous/MixedEasy2 minQB

ChemistryEasysingle choice

Number of -OH groups in open-chain glucose are :

Answer:

Solution:

Open-chain glucose is $HOC H_{2} - (CHOH)_{4} - CHO$ : four secondary $OH$ groups and one primary $OH$ = 5 (the sixth oxygen is the $CHO$ ).

Stream:JEESubject:ChemistryTopic:NomenclatureSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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