Chemistry - Nomenclature Question with Solution | TestHub

With three substituents the locant set {1,2,4} is the lowest possible. $\mathrm{Br}$ gets 1 (first alphabetically), $\mathrm{N}{\mathrm{O}}_2$ is then on ${\mathrm{C}}_2$ and $\mathrm{Cl}$ on ${\mathrm{C}}_4$.

Name: 1-bromo-4-chloro-2-nitrobenzene.