Chemistry - Nomenclature Question with Solution | TestHub

ChemistryNomenclatureDEGREE OF UNSATURATION AND HOMOLOGOUS SERIESMedium2 minQB
ChemistryMediummatching list

List - I

List - II

(P)

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(1)

(Q)

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(2) Only have 2°H

(R)

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(3) Hetero atoms are 6

(S)

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(4)

 

(5)

Options:

Answer:
B
Solution:

P (5) [DOU = 16]:

Contains 3 benzene rings ().

Contains 1 CN group (2), 1 COOH group (1), and 1 NO₂ group (1).

Total Degree of Unsaturation (DOU) = .

 

Q (4) [Melamine structure mismatch in option]:

According to the official answer options, Q matches with 4. (Note: Melamine actually has a DOU = 4 and 6 heteroatoms, but it is matched to 4 here to fit Option B of the question paper).

 

R (1) [DOU = 5]:

Paracetamol contains 1 benzene ring (4) and 1 carbonyl group (C=O) from the amide (1).

Total DOU = .

 

S (2) [Only have 2° H]:

In this structure (naphthalene with two phenyl rings), every single carbon bearing a hydrogen atom is bonded to exactly two other carbon atoms (2° carbons). Therefore, it contains only 2° hydrogens.

 

Correct Option: (B) P 5; Q 4; R 1; S 2

Stream:JEESubject:ChemistryTopic:NomenclatureSubtopic:DEGREE OF UNSATURATION AND HOMOLOGOUS SERIES
2mℹ️ Source: QB

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