Arrange the carbanions, CH 3 3 C − , C − Cl 3 , CH 3 2 C − H , C 6 H 5 C − H 2 in order of their decreasing stability:

As 2 o carbanion is more stable than 3 o due to less + I in 2 o then 3 o . As C l is – I group so it will make C - C l 3 highly stable. C 6 H 5 C - H 2 is resonance stabilized hence the correct order of stability is given as C - C l 3 M a x . [ - I ] > C 6 H 5 C - H 2 > C H 3 2 C - > C H 3 3 M a x . [ + I ] C -

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Chemistry - Nomenclature Question with Solution | TestHub

ChemistryNomenclatureMiscellaneous/MixedEasy2 minPYQ_2020

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Arrange the carbanions, ${({CH}_{3})}_{3} \bar{C}, \bar{C} {Cl}_{3}, {({CH}_{3})}_{2} \bar{C} H, C_{6} H_{5} \bar{C} H_{2}$ in order of their decreasing stability:

Options:

Answer:

Solution:

As $2^{o}$ carbanion is more stable than $3^{o}$ due to less $[+ I]$ in $2^{o}$ then $3^{o}$ . As $C l$ is $[- I]$ group so it will make $\bar{C} C l_{3}$ highly stable. $C_{6} H_{5} \bar{C} H_{2}$ is resonance stabilized hence the correct order of stability is given as
$\underset{M a x . [- I]}{\bar{C} C l_{3}} > C_{6} H_{5} \bar{C} H_{2} > {(C H_{3})}_{2} \bar{C} > \underset{M a x . [+ I]}{{(C H_{3})}_{3}^{}} \bar{C}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:NomenclatureSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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