Chemistry - Nomenclature Question with Solution | TestHub

$\mathrm{p}{\mathrm{K}}_{\mathrm{b}}\propto \frac{1}{{\mathrm{K}}_{\mathrm{b}}}\propto \frac{1}{\mathrm{B}\mathrm{a}\mathrm{s}\mathrm{i}\mathrm{c }\mathrm{}\mathrm{}\mathrm{s}\mathrm{t}\mathrm{r}\mathrm{e}\mathrm{n}\mathrm{g}\mathrm{t}\mathrm{h}}$
As basic nature decreases in the order (2) > (1) > (3). So$\mathrm{p}{\mathrm{K}}_{\mathrm{b}}$order is as follows
$\left(2\right)<\left(1\right)<\left(3\right)$