Chemistry - Nomenclature Question with Solution | TestHub

ChemistryNomenclatureMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

The equilibrium constant for the following reaction is

Answer:

Solution:

Subtracting (ii) from (i) gives the desired equation,

Hence equilibrium constant $= \frac{1 0^{- 9}}{1 0^{- 20}} = 1 0^{11} .$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:NomenclatureSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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