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ChemistryNomenclatureMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

The ammonia $(N H_{3})$ released on quantitative reaction of 0.6 g urea $(N H_{2} C O N H_{2})$ with sodium hydroxide (NaOH) can be neutralized by

Answer:

Solution:

$2 \times m o l e s o f N H_{3}$ = moles of urea
moles of $N H_{3} =$ moles of HCl
$\frac{100 \times 0.2}{1000} =$ moles of HCl $= 0.02$ mole of HCl

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:NomenclatureSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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