Potassium Chlorate is widely used as a source of pure oxygen since it generates pure oxygen on heating strongly.( $K Cl O_{3} \to K Cl + O_{2}$ )
Calculate the percent loss in weight after complete decomposition of a pure sample of potassium chlorate. ( $K = 39, Cl = 35.5$ )

Question

Potassium Chlorate is widely used as a source of pure oxygen since it generates pure oxygen on heating strongly.( $K Cl O_{3} \to K Cl + O_{2}$ )

Calculate the percent loss in weight after complete decomposition of a pure sample of potassium chlorate. ( $K = 39, Cl = 35.5$ )

TestHub · Accepted Answer

​ 122.5 ( 1 mole ) ​ KClO 3 ​ ( s ) ​ ​ → KCl ( s ) + 48 gm ( 2 3 ​ mole ) ​ 2 3 ​ O 2 ​ ( g ) ↑ ​ ​ ​ % loss = 122.5 48 ​ × 100 = 39.18 ​

Chemistry - Mole Concept Question with Solution | TestHub