A sample of MgSO 4 contains 8 × 1 0 20 ' O ' atoms what is the mass of ' S ' in the sample?

In MgSO 4 ⇒ Mole of O atom = 6 × 1 0 23 8 × 1 0 20 = 1.33 × 1 0 − 3 ⇒ Mole of S = 4 Moles of ′ O ′ atom = 0.33 × 1 0 − 3 moles ⇒ Mole of S atom = 0.33 × 1 0 − 3 × 32 = 1.06 × 1 0 − 2 gm

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A sample of $MgSO_{4}$ contains $8 \times 1 0^{20}$ ' O ' atoms what is the mass of ' S ' in the sample?

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Answer:

Solution:

In $MgSO 4 \Rightarrow$ Mole of O atom $= \frac{8 \times 1 0 ^{20}}{6 \times 1 0 ^{23}} = 1.33 \times 1 0^{- 3}$

⇒ Mole of $S = \frac{Moles of ^{'} O ^{'} atom}{4} = 0.33 \times 1 0^{- 3}$ moles

⇒ Mole of S atom $= 0.33 \times 1 0^{- 3} \times 32$

$= 1.06 \times 1 0^{- 2} gm$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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