Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptDetection and Estimation of ElementsMedium2 minQB

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Passage / Comprehension

Vitamin C ( $M = 176$ ) is a compound of C, H, and O found in many natural sources, especially citrus fruits. When a 2 gm sample of vitamin C is placed in a combustion chamber and burned, the following data is obtained:

Mass of KOH after combustion: 85.35 g

Mass of KOH before combustion: 82.35 g

Mass of anhydrous CaCl₂ after combustion: 37.96 g

Mass of anhydrous CaCl₂ before combustion: 37.14 g

Mass of C in sample is :

Options:

Answer:

Solution:

Mass of $CO_{2}$ produced $= 85.35 - 83.85 = 1.5 g$

∴ Percentage of $C = \frac{12}{44} \times \frac{1.5}{1.0} \times 100 = 40.9%$

Mass fo $H_{2} O$ produced $= 37.96 - 37.55 = 0.41 g$

∴ Percentage of $H = \frac{2}{18} \times \frac{0.41}{1.0} \times 100 = 4.56%$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Detection and Estimation of Elements

⏱ 2mℹ️ Source: QB

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