Match the following: List - I List - II (A) 32 g each of O 2 and S (P) 2 moles of Fe (B) 2 gram-molecule of K 3 [ Fe ( CN ) 6 ] (Q) 3 moles of ozone molecule (C) 144 g of oxygen atom (R) one mol

Question

Match the following: List - I List - II (A) 32 g each of O 2 ​ and S (P) 2 moles of Fe (B) 2 gram-molecule of K 3 ​ [ Fe ( CN ) 6 ​ ] (Q) 3 moles of ozone molecule (C) 144 g of oxygen atom (R) one mole (D) From 168 g of iron, 6.022 × 1 0 23 atoms of iron are removed, the iron left (S) 12 moles of carbon atoms

TestHub · Accepted Answer

Question Explanation: Match Column I with Column II

Concept: This question is based on basic mole.

Solution:

(A) 32 g each of $O_{2}$ and $S = \frac{32}{32} = 1$ mole

(B) 2 gram-molecule of $K_{3} [Fe (CN)_{6}] \Rightarrow$ has 2 moles of $Fe \Rightarrow$ and 12 moles of C -atom

(C) 144 g of oxygen atom $= \frac{144}{16} = 9$ mole of ' O ' atom

∴ Moles of $O_{3} = \frac{9}{3} = 3$

(D) from 168 g i.e. 3 moles $Fe \Rightarrow 1$ mole Fe is removed i.e. $\Rightarrow 2$ moles of Fe is left.

Final Answer: A-(R); B-(P,S); C-(Q); D-(P).

Chemistry - Mole Concept Question with Solution | TestHub

Options:

Doubts & Discussion

List - I	List - II
(A) 32 g each of $O_{2}$ and S	(P) 2 moles of Fe
(B) 2 gram-molecule of $K_{3} [Fe (CN)_{6}]$	(Q) 3 moles of ozone molecule
(C) 144 g of oxygen atom	(R) one mole
(D) From 168 g of iron, $6.022 \times 1 0^{23}$ atoms of iron are removed, the iron left	(S) 12 moles of carbon atoms