Chemistry - Mole Concept Question with Solution | TestHub
Match the columns.
List - I | List - II |
|---|---|
(A) 5 m of NaOH solution ( ) Molarity of solution is | (P) 16 M |
(B) 250 ml of solution provides 64 g of . Molarity of solution is | (Q) 1 M |
(C) 100 ml of solution (dsolution ) is mixed with 400 ml of water, density of fi nal solution . Molarity of resulting solution is | (R) 2.5 M |
(D) 100 ml of solution is mixed with 100 ml of solution ( ml). Molarity of ions in the resulting solution is | (S) 0.227 M |
Options:
Answer:
Solution:
(A) 5 m NaOH
5 moles NaOH in 1000 gm solvent
Mass of solution
Volume of solution
Molarity
(B)
(D) NaCl
100 ml (ppt)
600 m moles
0.6 moles Mass = 100 x 8 gm
= 800 gm
17% (w/W)
100 gm → 17 gm AgNO3
800 gm 17 x 8 gm AgNO3
=136 gm AgNO3
Moles = 136/170 = 0.8 moles
(L.R.)
0.6 moles 0.8 moles
- 0.2 moles
Moles of Ag+ = 0.2 moles
Total volume = 100 ml + 100 ml = 0.2 L
Molarity = 0.2 moles/0.2 L = 1 M