Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptCalculation of moleMedium2 minQB
ChemistryMediummatching list

Match the columns.

List - I

List - II

(A) 5 m of NaOH solution ( ) Molarity of solution is

(P) 16 M

(B) 250 ml of solution provides 64 g of . Molarity of solution is

(Q) 1 M

(C) 100 ml of solution (dsolution ) is mixed with 400 ml of water, density of fi nal solution . Molarity of resulting solution is

(R) 2.5 M

(D) 100 ml of solution is mixed with 100 ml of solution ( ml). Molarity of ions in the resulting solution is

(S) 0.227 M

Options:

Answer:
A
Solution:

(A) 5 m NaOH

5 moles NaOH in 1000 gm solvent

Mass of solution

Volume of solution

Molarity

(B)

 

(D) NaCl

100 ml (ppt)

600 m moles

0.6 moles Mass = 100 x 8 gm

= 800 gm

17% (w/W)

100 gm → 17 gm AgNO3

800 gm 17 x 8 gm AgNO3

=136 gm AgNO3

Moles = 136/170 = 0.8 moles

 

(L.R.)

0.6 moles 0.8 moles

- 0.2 moles

Moles of Ag+ = 0.2 moles

Total volume = 100 ml + 100 ml = 0.2 L

Molarity = 0.2 moles/0.2 L = 1 M

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole
2mℹ️ Source: QB

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