Chemistry - Mole Concept Question with Solution | TestHub
ChemistryMole ConceptLaws of Chemical CalculationsMedium2 minQB
ChemistryMediumnumerical
A gaseous mixture of and at 400 K & 1 atm was added with excess of & subjected to sparking in a rigid container (volume constant). If pressure of obtained at 400 K in same volume is 0.9 atm and that of vapour is 0.8 atm. If moles of and are equal, and the ratio of pressure of and gases in the original mixture is 1 : x, then the value 'x' is.
Answer:
1.50
Solution:
Let the initial moles be: C₂H₄ = , CH₄ = , CO = , N₂ = .
From combustion,
From water vapor formed,
Hence,
Using the given relation and Dalton's law, the pressure ratio is:
Therefore,
Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Laws of Chemical Calculations
⏱ 2mℹ️ Source: QB
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