A metal oxide has the formula X 2 O 3 . It can be reduced by hydrogen to give free metal and water. 0.1596 g of metal oxide requires 6 mg of hydrogen for complete reduction. The atomic mass of metal i

Question

A metal oxide has the formula X 2 O 3 . It can be reduced by hydrogen to give free metal and water. 0.1596 g of metal oxide requires 6 mg of hydrogen for complete reduction. The atomic mass of metal in amu is

TestHub · Accepted Answer

X 2 O 3 1 m o l ( 2 a + 48 ) + 3 H 2 3 m o l 6 g → 2 X + 3 H 2 O 0.006 g H 2 is required by 0.1596 g oxide So 6 g H 2 will be require by 159.6 g oxide So 2 a + 48 = 159.6 a = 55.8 where, a = atomic mass of metal M.

Chemistry - Mole Concept Question with Solution | TestHub

Options:

Doubts & Discussion