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Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

0.73 g of organic compound on oxidation gave 1.32 g of carbon dioxide. The percentage of carbon in the given compound will be

Options:

Answer:

Solution:

$% o f c a r b o n = \frac{12}{44} \times \frac{w t . o f C O_{2}}{w t . o f s a m p l e} \times 100 = \frac{12}{44} \times \frac{1.32}{0.73} \times 100 = 49.32$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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