Chemistry - Mole Concept Question with Solution | TestHub

$\begin{array}{lllllll}\underset{\begin{array}{l}2.4\mathrm{g}\\ 0.1\mathrm{m}\mathrm{o}\mathrm{l}\\ -0.05\\ 0.05\mathrm{m}\mathrm{o}\mathrm{l}\end{array}}{\mathrm{M}\mathrm{g}}& +& \underset{\begin{array}{l}(1\mathrm{M},100\mathrm{m}\mathrm{l})\\ 0.1\mathrm{m}\mathrm{o}\mathrm{l}\end{array}}{2\mathrm{H}\mathrm{C}\mathrm{l}}& \to & \mathrm{M}\mathrm{g}\mathrm{C}{\mathrm{l}}_2& +& {\mathrm{H}}_2\end{array}$
HCl is a limiting reagent
0.1 mol HCl give$\frac{0.1}{2}$mol${\mathrm{H}}_2$or 1.12 lit${\mathrm{H}}_2$at STP
0.05 mol Mg left
So option D is wrong.