Chemistry - Mole Concept Question with Solution | TestHub

$\mathrm{C=}\mathrm{}\frac{20}{12}=1.66=1$
$\mathrm{N=}\mathrm{}\frac{46.66}{14}=3.33=2$
$\mathrm{H=}\mathrm{}\frac{6.66}{1}=6.66=4$
$\mathrm{O=}\mathrm{}\frac{\mathrm{}26.68}{16}=1.66=1$
Empirical formula of compound$\mathrm{C}{\mathrm{N}}_2{\mathrm{H}}_4\mathrm{O}$
Since, this organic compound contains carbon, hydrogen, nitrogen and oxygen and on heating with alkali liberates$\mathrm{N}{\mathrm{H}}_3$the organic compound must be urea.
$\mathrm{N}{\mathrm{H}}_2\mathrm{C}\mathrm{O}\mathrm{N}{\mathrm{H}}_2+2\mathrm{N}\mathrm{a}\mathrm{O}\mathrm{H}\to 2\mathrm{N}{\mathrm{H}}_3+\mathrm{N}{\mathrm{a}}_2\mathrm{C}{\mathrm{O}}_3$