245 g impure sample of K C l O 3 s on heating gives 12 g O 2 g according to 2 KClO 3 s → 2 KCl s + 3 O 2 g Calculate % purity of sample ?

2 KClO 3 → 2 KCl + 3 O 2 Let the % purity = x Mole of K C l O 3 = 245 122.5 × x 100 = 2 x 100 Mole of O 2 = 2 x 100 × 3 2 2 x 100 × 3 2 × 32 = 12 (% purity of sample) x = 12 .5

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ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

$245 g$ impure sample of $K C l O_{3} (s)$ on heating gives $12 g O_{2} (g)$ according to $2 {KClO}_{3} (s) \to 2 KCl (s) + 3 O_{2} (g)$
Calculate % purity of sample ?

Answer:

12.50

Solution:

$2 {KClO}_{3} \to 2 KCl + 3 O_{2}$
Let the % purity = $x$
Mole of $K C l O_{3}$ = $\frac{245}{122.5} \times \frac{x}{100}$ = $\frac{2 x}{100}$
Mole of $O_{2}$ = $\frac{2 x}{100} \times \frac{3}{2}$
$\frac{2 x}{100} \times \frac{3}{2} \times 32 = 12$
(% purity of sample) $x = 12 .5$

Stream:NTA_ABHYASSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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