Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

A metal $M$ forms the sulphate $M_{2} {(S O_{4})}_{3} .$ A $0.596$ gram sample of the sulphate reacts with excess $B a C l_{2}$ to give $1.220 g B a S O_{4} .$ What is the atomic weight of $M$ (in g/mol)?

Options:

Answer:

Solution:

Mole of $B a S O_{4} = \frac{1.22}{233.3}$
Moles of $M_{2} {(S O_{4})}_{3} = \frac{1.22}{233.3} \times \frac{1}{3}$
$= 1.743 \times 10^{- 3}$
Wt. of $M_{2} {(S O_{4})}_{3} = 0.596$
$∴ 1.743 \times 10^{- 3} (2 M + 96 \times 3) = 0.596$
$M = 26.9$

Stream:NTA_ABHYASSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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