Chemistry - Mole Concept Question with Solution | TestHub

The given reaction is as follows $2{\mathrm{KHCO}}_3⟶{\mathrm{K}}_2{\mathrm{CO}}_3(\mathrm{g})+{\mathrm{CO}}_2(\mathrm{g})+{\mathrm{H}}_2\mathrm{O}$ (l) $\because 2$ moles of ${\mathrm{KHCO}}_3$ gives $=1\mathrm{mol}$ of ${\mathrm{K}}_2{\mathrm{CO}}_3$ $\therefore 1$ moles of ${\mathrm{KHCO}}_3$ gives $=1/2\mathrm{mol}$ of ${\mathrm{K}}_2{\mathrm{CO}}_3$ $\therefore 33\mathrm{gm}\left(\frac{33}{100}\mathrm{mol}\right)$ of ${\mathrm{KHCO}}_3$ gives $=\frac{33}{200}$ mol of ${\mathrm{K}}_2{\mathrm{CO}}_3$ Similarly, $33\mathrm{gm}\left(\frac{33}{100}\mathrm{mol}\right)$ of ${\mathrm{KHCO}}_3$ gives $=\frac{33}{200}\mathrm{mol}$ of ${\mathrm{CO}}_2$ Total moles of gases $=\frac{33}{200}+\frac{33}{200}=\frac{66}{200}\mathrm{mol}$ $\begin{array}{rl}1\mathrm{mol}\text{ of gas }& =224\mathrm{l}\text{ volume }\\ \therefore \frac{66}{200}\mathrm{mol}\text{ of gas }& =\frac{66}{200}\times 22.4=7.46\mathrm{l}.\end{array}$