Chemistry - Mole Concept Question with Solution | TestHub

The concerned chemical reactions are (i) $\underset{64\mathrm{kg}}{{\mathrm{CaC}}_2+2{\mathrm{H}}_2\mathrm{O}\to \mathrm{Ca}(\mathrm{OH}{)}_2}+\underset{\text{ Ethyne, }26\mathrm{kg}}{{\mathrm{C}}_2{\mathrm{H}}_2}$ (ii) ${\mathrm{C}}_2{\mathrm{H}}_2+{\mathrm{H}}_2\to \underset{\text{ Ethylene },28\mathrm{kg}}{{\mathrm{C}}_2{\mathrm{H}}_4}$ $$\text{ (iii) }{\mathrm{nC}}_2{\mathrm{H}}_2\to {\left[-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\right]}_{\mathrm{n}}$$ $\begin{array}{ll}\mathrm{n}\times 28\mathrm{kg}& \mathrm{n}\times 28\mathrm{kg}\text{ polythene }\\ \text{ or }28\mathrm{kg}& \text{ or }28\mathrm{kg}\end{array}$ Thus $64\mathrm{kg}$ of ${\mathrm{CaC}}_2$ gives $26\mathrm{kg}$ of acetylene which in turn gives $28\mathrm{kg}$ of ethylene whose $28\mathrm{kg}$ gives $28\mathrm{kg}$ of the polymer, polythene.