Chemistry - Mole Concept Question with Solution | TestHub

The required neutralisation reaction is, $2{\mathrm{NaHCO}}_3+{\mathrm{H}}_2{\mathrm{SO}}_4⟶{\mathrm{Na}}_2{\mathrm{SO}}_4+2{\mathrm{H}}_2\mathrm{O}+2{\mathrm{CO}}_2$$m$-moles of ${\mathrm{H}}_2{\mathrm{SO}}_4=M\times V_{\mathrm{mL}}=40.0\times 0.1=4\mathrm{m}$-mole or m-moles of ${\mathrm{NaHCO}}_3$ neutralised $=4\times 2=8\mathrm{m}$-mole But, m-mole $=\frac{w}{m}\times 1000$ $\begin{array}{rl}8& =\frac{w}{84}\times 1000\\ \Rightarrow w& =\frac{84\times 8}{1000}\Rightarrow w=0.672\mathrm{g}\end{array}$