An ore of iron contains FeS and some non-volatile impurity. On roasting if this ore converts all FeS into Fe 2 O 3 and 8% loss in weight was observed. The mass percentage of FeS in ore is FeS + O

Question

An ore of iron contains FeS and some non-volatile impurity. On roasting if this ore converts all FeS into Fe 2 ​ O 3 ​ and 8% loss in weight was observed. The mass percentage of FeS in ore is FeS + O 2 ​ ⟶ Fe 2 ​ O 3 ​ + SO 2 ​

TestHub · Accepted Answer

Reaction: 4 F e S + 7 O 2 ​ → 2 F e 2 ​ O 3 ​ + 4 S O 2 ​ Observed weight loss: 8% F r a c t i o na ll oss p er F e S = M a ss F e S M a ss S O 2 ​ ​ = 352 352 − 320 ​ = 0.091 M a ss F e S = F r a c t i o na ll oss O b ser v e d l oss ​ = 0.091 8 ​ ≈ 88

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