4 M ( s ) + 8 CN − ( aq ) + 2 H 2 O ( aq ) + O 2 ( g ) → 4 [ M ( CN ) 2 ] − ( aq ) + 4 OH − ( aq ) . Here,

M ∘ ( s ) + CN − ( aq ) oxidation [ M + 2 ( CN ) 2 ] − O 2 ∘ ( g ) reduction [ OH − 2 ] − ( aq )

Chemistry - Metallurgy Question with Solution | TestHub

ChemistryMetallurgyEllingham diagram & Reduction methods, Refining of metalMedium2 minQB

ChemistryMediummultiple choice

$4 M (s) + 8 CN^{-} (aq) + 2 H_{2} O (aq) + O_{2} (g) \to 4 [M (CN)_{2}]^{-} (aq) + 4 OH^{-} (aq)$ .

Here,

Answer:

A, B

Solution:

$M \circ (s) + CN^{-} (aq) oxidation [M^{+ 2} (CN)_{2}]^{-}$

$O_{2}^{\circ} (g) reduction [OH^{- 2}]^{-} (aq)$

Stream:JEESubject:ChemistryTopic:MetallurgySubtopic:Ellingham diagram & Reduction methods, Refining of metal

⏱ 2mℹ️ Source: QB

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