When a sulphide ore of a noble metal is treated with excess of cyanide solution then a soluble complex is formed which when treated with Zn , a soluble complex (X) is formed and noble metal is obtaine

Question

When a sulphide ore of a noble metal is treated with excess of cyanide solution then a soluble complex is formed which when treated with Zn , a soluble complex (X) is formed and noble metal is obtained as residue. Which of the following statement is correct regarding (X)

TestHub · Accepted Answer

The noble metal (M) reacts with cyanide to form $[M (CN)_{2}]^{-}$ . When treated with Zn, the reaction is $2 [M (CN)_{2}]^{-} + Z n \to [Z n (CN)_{4}]^{2 -} + 2 M$ . Thus, (X) is $[Z n (CN)_{4}]^{2 -}$ .

A. Zn is in the anionic part of $[Z n (CN)_{4}]^{2 -}$ .

B. Zn in $[Z n (CN)_{4}]^{2 -}$ is $Z n^{2 +}$ (d¹⁰ configuration), so its hybridization is $s p^{3}$ .

C. EAN of $Z n^{2 +}$ in $[Z n (CN)_{4}]^{2 -}$ is $30 - 2 + 2 \times 4 = 36$ .

D. Cyanide is a $π$ -acceptor ligand, so it shows synergic bonding.

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JEE Advanced 2027 (Class 12)