From the given minerals calculate the number of minerals in which atleast two different metals present in oxidation state $\geq + 2$ .
Zincite, chromite, Illemanite, cryolite, dolomite iron pyrite, carnalite

Question

From the given minerals calculate the number of minerals in which atleast two different metals present in oxidation state $\geq + 2$ .

Zincite, chromite, Illemanite, cryolite, dolomite iron pyrite, carnalite

TestHub · Accepted Answer

To identify minerals with at least two different metals having an oxidation state $\geq + 2$ :

1. Zincite (ZnO): Zn is +2. Only one metal.

2. Chromite (FeCr₂O₄): Fe is +2, Cr is +3. Two metals with oxidation states $\geq + 2$ .

3. Ilmenite (FeTiO₃): Fe is +2, Ti is +4. Two metals with oxidation states $\geq + 2$ .

4. Cryolite (Na₃AlF₆): Al is +3. Only one metal with oxidation state $\geq + 2$ .

5. Dolomite (CaMg(CO₃)₂): Ca is +2, Mg is +2. Two metals with oxidation states $\geq + 2$ .

6. Iron pyrite (FeS₂): Fe is +2. Only one metal.

7. Carnallite (KCl·MgCl₂·6H₂O): Mg is +2. Only one metal with oxidation state $\geq + 2$ .

Thus, Chromite, Ilmenite, and Dolomite satisfy the condition.

Number of minerals = 3.

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