The first and second ionisation enthalpies of a metal are 496 and 4560 kJ m o l - 1 , respectively. How many moles of HCl and H 2 S O 4 , respectively, will be needed to react completely with 1 mole o

Question

The first and second ionisation enthalpies of a metal are 496 and 4560 kJ m o l - 1 , respectively. How many moles of HCl and H 2 S O 4 , respectively, will be needed to react completely with 1 mole of the metal hydroxide?

TestHub · Accepted Answer

Metal: First ionization enthalpies = 496 kJ/mole
Second ionization enthalpies = 4560 kJ/mol
According to the given information of ionization enthalpies, metal belong to first group i.e. Monovalent cation
$\underset{1 m o l e}{M O H} + \underset{1 m o l e}{H C l} \to M C l + H_{2} O$
$\underset{1 m o l e}{2 M O H} + \underset{1 / 2 m o l e}{H_{2} S O_{4}} \to M_{2} S O_{4} + H_{2} O$
That is 1 mole HCl and 0.5 mole $H_{2} S O_{4}$ are needed respectively.

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