Chemistry - Metallurgy Question with Solution | TestHub
ChemistryMetallurgyEllingham diagram & Reduction methods, Refining of metalHard2 minQB
ChemistryHardsingle choice
Match Column 1 with Column 2.
Column 1 | Column 2 |
|---|---|
P Blistered Cu | 1 Aluminium |
Q Blast furnace | 2 2Cu₂O + Cu₂S → 6Cu + SO₂ |
R Reverberatory furnace | 3 Iron |
S Hall-Héroult process | 4 FeO + SiO₂ → FeSiO₃ |
| 5 2Cu₂S + 3O₂ → 2Cu₂O + 2SO₂ |
Options:
Answer:
A
Solution:
Blistered copper forms through self-reduction (P-2); the blast furnace makes iron (Q-3); FeO forms silicate slag in the reverberatory furnace (R-4); the Hall-Héroult process makes aluminium (S-1).
Stream:JEESubject:ChemistryTopic:MetallurgySubtopic:Ellingham diagram & Reduction methods, Refining of metal
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
